# Nitrous oxide et la bataille thermodynamique : Star Wars au niveau moléculaire

**URL:** <https://www.med-dit.com/t/nitrous-oxide-et-la-bataille-thermodynamique-star-wars-au-niveau-moleculaire/1759>\
**Category:** Free\
**Tags:** switzerland, sfo, chimie-générale, genève, equilibre-chimique\
**Created:** [April 25, 2025, 1:07am UTC](https://www.med-dit.com/t/nitrous-oxide-et-la-bataille-thermodynamique-star-wars-au-niveau-moleculaire/1759 "2025-04-25T01:07:02Z")\
**Posts on this page:** 1\
**Page:** 1

<div class="post-metadata">

**Author:** ![exa-MED](https://yyz2.discourse-cdn.com/flex004/user_avatar/www.med-dit.com/exa-med/32/29_2.png) [@exa-MED](https://www.med-dit.com/u/exa-MED)\
**Post date:** [April 25, 2025, 1:07am UTC](https://www.med-dit.com/t/nitrous-oxide-et-la-bataille-thermodynamique-star-wars-au-niveau-moleculaire/1759/1 "2025-04-25T01:07:02Z")

</div>

![post-thumbnail](https://canada1.discourse-cdn.com/flex004/uploads/med_dit/original/2X/8/818a918595e9a80954d5a154eb5c5677dde8e720.jpeg)

🎯 Type A 🎯  
**A  
46. Je recherche le delta G° de la réaction N2O(g) + ½ O2 (g) ↔ 2NO (g) sachant que les constantes d’équilibres sont:  
N2(g) + ½ O2 (g) ↔ N20 (g) K1 = 4 x 10 ^4  
N2(g) + O2(g) ↔ 2NO (g) K2 = 2 x 10^ 3  
R = 8.3145 J/(mol K), T = 25°C**

_Poll ([view on site](https://www.med-dit.com/t/nitrous-oxide-et-la-bataille-thermodynamique-star-wars-au-niveau-moleculaire/1759/1))_

> **\*\*🧙✨🔍📘👉 CORRECTION ICI 👈📘🔍✨🧙\*\***
>
> **Réponse attendue :** E
> 
> https://player.vimeo.com/video/1074946874
